MCA Entrance Previous Year Question Bank

The product of perpendiculars from $(2,-1)$ to the pair of lines $2x^2+6xy+y^2=0$ is:

The equation of line passing through $(-2,3)$ and perpendicular to $2x-3y+6=0$ is given by:

The distance between the pair of straight lines $x^2+2\sqrt{3}xy+2y^2+4x+1=0$ is:

If $(-4,5)$ is one vertex and $7x-y+8=0$ is one diagonal of a square, then the equation of the other diagonal is:

If the two pairs of lines $x^2-2mxy-y^2=0$ and $x^2-2nxy-y^2=0$ are such that one of them represents the bisector of the angles between the other, then:

If $2x^2+7xy+3y^2+8x+14y+\lambda =0$ represents a pair of straight lines, the value of $\lambda$ is

If x² + 3xy + 2y² - x - 4y - 6 = 0 represents a pair of straight lines, their point of intersection is

Equation of the line perpendicular to x - 2y = 1 and passing through (1, 1) is:

Let a , b , c , d be non zero numbers . If the point of intersection of the line 4ax + 2ay + c =0 and 5bx + 2by + d = 0 lies in the fourth quadrant and is equidistance from the two are then

The obtuse angle between the lines $2y=x+1$ and $y=3x+2$ is: