If x² + 3xy + 2y² - x - 4y - 6 = 0 represents a pair of straight lines, their point of intersection is
Explanation
Concept:
A partial derivative of a function of several variables is its derivative with respect to one of those variables, with the others held constant.
Example: partial differentiate w.r.t. x then y will be constant and vice versa.(for function containing x and y variables).
Calculation:
Let, ϕ(x,y)=x2+3xy+2y2−x−4y−6=0
Taking partial derivative w.r.t. x, we get
dxdϕ=2x+3y−1=0⋅⋅⋅(1)
Taking partial derivative w.r.t. x, we get
<br>dydϕ=3x+4y−4=0⋅⋅⋅(2)
Multiplying (1) by 3 and (2) by 2, we get
6x+9y−3=0... (3) and 6x+8y−8=0... (4)
Now, subtracting (4) from (3), we get
<br>y+5=0⇒y=−5
From (1),
2x+3(−5)−1=0
<br>⇒x=8
So, the point of intersection is (8, -5)
Hence, option (3) is correct.