Equation of the line perpendicular to x - 2y = 1 and passing through (1, 1) is:
Explanation
Concept:
- If two lines y=m1x+c1 and y=m2x+c2 are perpendicular to each other, then m1×m2=−1.
- If a point P(a, b) lies on a curve f(x,y)=0, then f(a,b)=0.
Calculation:
Let us first find out the slope (m2) of the second line.
The equation of the first line is x−2y=1.
It can be written as y=21x−21. Therefore, m1=21.
Now, m1×m2=−1
⇒21×m2=−1
⇒m2=−2
∴ The equation of the second line can be written as y=−2x+c.
Since this line passes through (1, 1), we must have:
1=(−2)(1)+c
⇒c=3.
Hence, the equation of the line is y=−2x+3.