WBJECA 2025 — Computer PYQ

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Question

WBJECA 2025 — Computer PYQ

WBJECA | Computer | 2025

Maximum data rate of a channel for a noiseless 3 KHz binary channel is

Choose the correct answer:

Explanation

To find the maximum data rate for a noiseless channel, we use the Nyquist Bit Rate formula. The formula is defined as:

$Maximum Data Rate = 2 \times B \times lo g_{2} (L)$

Where:

$B$ = Bandwidth of the channel (in Hertz)
$L$ = Number of signal levels (for a binary channel, $L = 2$ )

Given Data:

$B = 3 KHz = 3000 Hz$
$L = 2$ (Since it is a binary channel)

Calculation:

Substituting these values into the formula:

$Data Rate = 2 \times 3000 \times lo g_{2} (2)$

Since $lo g_{2} (2) = 1$ :

$Data Rate = 2 \times 3000 \times 1 = 6000 bps$

Therefore, the maximum data rate is 6000 bps.

Correct Option: (B) 6000 bps