NIMCET 2026 — Reasoning PYQ

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Question

NIMCET 2026 — Reasoning PYQ

NIMCET | Reasoning | 2026

Runs scored by Sachin in a charity match are 10 more than the balls faced by Lara. The number of balls faced by Sachin is 5 less than the runs scored by Lara. Together, they have scored 105 runs and Sachin faced 10 balls less than the balls faced by Lara. How many runs were scored by Sachin?

Choose the correct answer:

Explanation

To solve this problem, we will use a system of linear equations. Let us define our variables first:

$R_{S}$ = Runs scored by Sachin
$R_{L}$ = Runs scored by Lara
$B_{S}$ = Balls faced by Sachin
$B_{L}$ = Balls faced by Lara

Step 1: Translate the statements into equations

Based on the text in image_8270dc.png, we can derive the following equations:

$R_{S} = B_{L} + 10$
$B_{S} = R_{L} - 5$
$R_{S} + R_{L} = 105$
$B_{S} = B_{L} - 10$

Step 2: Solve the system of equations

From equation (4), we can express $B_{L}$ in terms of $B_{S}$ :

$B_{L} = B_{S} + 10$

Now, substitute this into equation (1) to find $R_{S}$ :

$R_{S} = (B_{S} + 10) + 10$

$R_{S} = B_{S} + 20$

From equation (2), we can express $R_{L}$ in terms of $B_{S}$ :

$R_{L} = B_{S} + 5$

Now, substitute the expressions for $R_{S}$ and $R_{L}$ into equation (3):

$(B_{S} + 20) + (B_{S} + 5) = 105$

$2 B_{S} + 25 = 105$

$2 B_{S} = 80$

$B_{S} = 40$

Step 3: Calculate the final answer

Now that we have $B_{S} = 40$ , we can substitute this back into our expression for $R_{S}$ :

$R_{S} = B_{S} + 20$

$R_{S} = 40 + 20$

$R_{S} = 60$

Conclusion:

The total runs scored by Sachin is 60. Therefore, the correct option is 3.