NIMCET 2008 — Reasoning PYQ

Q: How do I solve NIMCET 2008 Reasoning questions?

Practice NIMCET 2008 Reasoning previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Reasoning questions?

NIMCET Reasoning questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2008 — Reasoning PYQ

NIMCET | Reasoning | 2008

Four friends-Arjan, Bhuvan, Guran and Lakha comparing the number of sheeps that they owned. It was found that Guran had ten more sheeps than Lakha. If Arjan gave one-third to Bhuvan and Bhuvan gave a quarter of what he then held to Guran, who then passed on a fifth of his holding to Lakha, they would all have an equal number of sheep. How many sheeps did each of them possess? Give the minimal possible answer.

Choose the correct answer:

Explanation

Let $A, B, G, L$ be the initial sheep and $E$ be the final equal number.

1. Given Condition:

G = L + 10 \quad \text{---(1)}

2. Transaction Equations:

Arjan: $\frac{2}{3}A = E \Rightarrow A = \frac{3}{2}E$
Bhuvan: $\frac{3}{4}(B + \frac{1}{3}A) = E \Rightarrow B + \frac{1}{2}E = \frac{4}{3}E \Rightarrow B = \frac{5}{6}E$
Guran: $\frac{4}{5}(G + \frac{1}{4}(B + \frac{1}{3}A)) = E \Rightarrow G + \frac{1}{3}E = \frac{5}{4}E \Rightarrow G = \frac{11}{12}E$
Lakha: $L + \frac{1}{5}(G + \frac{1}{3}E) = E \Rightarrow L + \frac{1}{4}E = E \Rightarrow L = \frac{3}{4}E$

3. Finding $E$ :

Substitute $G$ and $L$ in (1):

\frac{11}{12}E = \frac{3}{4}E + 10

\frac{11E - 9E}{12} = 10 \Rightarrow 2E = 120 \Rightarrow E = 60

4. Initial Values:

$A = \frac{3}{2}(60) = 90$
$B = \frac{5}{6}(60) = 50$
$G = \frac{11}{12}(60) = 55$
$L = \frac{3}{4}(60) = 45$

Calculated values: 90, 50, 55, 45.

Correct Option: (d) None of these