MAH-CET 2026 — Reasoning PYQ

Step 1: Set up the algebraic equation

Let the total required quantity of the alloy be $x\text{ grams}$.

According to the question, the alloy contains $41\%$ bronze, and we need to obtain exactly $900\text{ grams}$ of pure bronze from it. We can write this relation mathematically as:

$$41\%\text{ of }x=900$$

Step 2: Solve for x

Convert the percentage value into its fractional equivalent and isolate $x$:

$$\frac{41}{100}\times x=900$$

$$41x=900\times 100$$

$$41x=90000$$

$$x=\frac{90000}{41}$$

Step 3: Perform the division

Let us divide $90000$ by $41$ step-by-step to arrive at the decimal value:

1. $90÷41=2$ with a remainder of $8$ (since $41\times 2=82$)

2. Bring down the first zero $\to 80$. Then, $80÷41=1$ with a remainder of $39$ (since $41\times 1=41$)

3. Bring down the second zero $\to 390$. Then, $390÷41=9$ with a remainder of $21$ (since $41\times 9=369$)

4. Bring down the final zero $\to 210$. Then, $210÷41=5$ with a remainder of $5$ (since $41\times 5=205$)

This gives us the whole number part: $2195$.

Now, let us find the digits after the decimal point using the remaining value of $5$:

• $50÷41=1$ with a remainder of $9$

• $90÷41=2$ with a remainder of $8$

$$x\approx 2195.1219\text{ g}$$

Rounding off to two decimal places gives $2195.12\text{ g}$.

Correct Answer

The correct option is (b) 2195.12.