NIMCET 2011 — Reasoning PYQ

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Question

NIMCET 2011 — Reasoning PYQ

NIMCET | Reasoning | 2011

Directions : Read the information given below and answer the questions that follow :
Four persons A, B, C and D play a cards game. They put Rs. 500 as stake money. When the game is over ‘C’ receives Rs. 19 more than ‘D’ and ‘B’ receives Rs. 21 less than ‘A’ whose amount was Rs. 2 less than the quarter of Rs. 500

Who get highest amount?

Choose the correct answer:

Explanation

1. Find the amount for A:

The problem states 'A' received Rs. 2 less than the quarter of Rs. 500.

A = \left( \frac{500}{4} \right) - 2

A = 125 - 2 = 123

A received Rs. 123.

2. Find the amount for B:

'B' receives Rs. 21 less than 'A'.

B = A - 21

B = 123 - 21 = 102

B received Rs. 102.

3. Find the combined amount for C and D:

Since the total sum is Rs. 500, we subtract the shares of A and B.

C + D = 500 - (A + B)

C + D = 500 - (123 + 102)

C + D = 500 - 225 = 275

4. Solve for C and D:

We are told 'C' receives Rs. 19 more than 'D'.

C = D + 19

Now, substitute this into the $C + D$ equation:

(D + 19) + D = 275

2D + 19 = 275

2D = 256

D = 128

D received Rs. 128.

Now, find C:

C = 128 + 19 = 147

C received Rs. 147.