NIMCET 2011 — Reasoning PYQ

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Question

NIMCET 2011 — Reasoning PYQ

NIMCET | Reasoning | 2011

Directions: Read the information given below and answer the questions that follow :
Four persons A, B, C and D play a cards game. They put Rs. 500 as stake money. When the game is over ‘C’ receives Rs. 19 more than ‘D’ and ‘B’ receives Rs. 21 less than ‘A’ whose amount was Rs. 2 less than the quarter of Rs. 500

How much money did ‘C’ get ?

Choose the correct answer:

Explanation

Step 1: Calculate the amount for 'A'

The problem states 'A' received Rs. 2 less than the quarter of Rs. 500.

\text{Quarter of 500} = \frac{500}{4} = 125

\text{Amount for A} = 125 - 2 = 123

Step 2: Calculate the amount for 'B'

'B' receives Rs. 21 less than 'A'.

\text{Amount for B} = 123 - 21 = 102

Step 3: Establish the relationship for 'C' and 'D'

Let the amount 'D' receives be $x$ .

'C' receives Rs. 19 more than 'D', so:

\text{Amount for C} = x + 19

Step 4: Use the total sum to find $x$

The sum of all four amounts must equal the total stake money of Rs. 500.

A + B + C + D = 500

123 + 102 + (x + 19) + x = 500

244 + 2x = 500

2x = 500 - 244

2x = 256

x = 128

Step 5: Calculate the final amount for 'C'

Now, substitute $x$ back into the expression for 'C':

\text{Amount for C} = x + 19

\text{Amount for C} = 128 + 19 = 147

Conclusion:

'C' received Rs. 147.

Correct Option:

(a) Rs. 147