Explanation
Solution:
Step 1: Sabse andar wale part ∣2A−1∣ ko solve karte hain
Property ∣kM∣=kn∣M∣ ka use karke:
Kyunki ∣A∣=2, isliye:
Step 2: Ab ∣Adj(2A−1)∣ nikalte hain
Property ∣Adj(M)∣=∣M∣n−1 ka use karke:
∣Adj(2A−1)∣=(∣2A−1∣)n−1=(2n−1)n−1=2(n−1)2
Step 3: Ab ∣2⋅Adj(2A−1)∣ nikalte hain
Fir se ∣kM∣=kn∣M∣ ka use karke:
∣2⋅Adj(2A−1)∣=2n⋅∣Adj(2A−1)∣=2n⋅2(n−1)2
Step 4: Poore expression ka determinant nikalte hain
∣Adj(2⋅Adj(2A−1))∣=∣2⋅Adj(2A−1)∣n−1
Step 5: Equation bana kar n ki value nikalte hain
Humein diya hai ki ye 284 ke barabar hai:
Is cubic equation mein agar hum n=5 rakhte hain:
53−2(52)+2(5)−85=125−50+10−85=135−135=0
Isliye, n=5 sahi jawab hai.
Final Answer: n=5