JEE 2023 — Mathematics PYQ
JEE | Mathematics | 2023The value of ∫π/3π/2sinx(1+cosx)(2+3sinx)dx is equal to:
Choose the correct answer:
- A.
310−3−loge3
310−3−loge3
Explanation
Solution
Split the integral:
For the second part: 1+cosx3=2cos2(x/2)3=23sec2(x/2).
∫23sec2(x/2)dx=3tan(x/2).
For the first part, use substitution t=tan(x/2), where sinx=1+t22t and cosx=1+t21−t2.
After partial fractions and integration, and applying limits [π/3,π/2] (where t goes from 1/3 to 1):
Final result calculation leads to:
Correct Option: (1)
Explanation
Solution
Split the integral:
For the second part: 1+cosx3=2cos2(x/2)3=23sec2(x/2).
∫23sec2(x/2)dx=3tan(x/2).
For the first part, use substitution t=tan(x/2), where sinx=1+t22t and cosx=1+t21−t2.
After partial fractions and integration, and applying limits [π/3,π/2] (where t goes from 1/3 to 1):
Final result calculation leads to:
Correct Option: (1)

