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Let Δ,∇∈{∧,∨} be such that (p→q)Δ(p∇q) is a tautology. Then
- A.
Δ=∨,∇=∨
(Correct Answer) - B.
Δ=∨,∇=∧
- C.
Δ=∨,∇=∧
Explanation
Checking Option (1): Δ=∨,∇=∨
The expression becomes:
Since p→q≡¬p∨q:
Using Associative and Commutative laws:
Since the result is always True (T), it is a tautology.
Explanation
Checking Option (1): Δ=∨,∇=∨
The expression becomes:
Since p→q≡¬p∨q:
Using Associative and Commutative laws:
Since the result is always True (T), it is a tautology.