JEE 2023 — Mathematics PYQ

Given: $(p\to q)\to (q\to p)$

Negation of above statement is
$\sim [(p\to q)\to (q\to p)]$
$\equiv [\sim p\to q\wedge q\to p]$
$\equiv p\to q\wedge \sim q\wedge q\wedge \sim p]$
$\equiv \sim p\vee q\wedge \sim q\wedge (\neg p]$