Explanation
Step 1: Inequality ko simplify karna
Dhyan se dekhne par, left side ek derivative ban raha hai:
dxd[xlogex⋅f(x)]=(x⋅x1+logex)f(x)+(xlogex)f′(x)
=(1+logex)f(x)+(xlogex)f′(x)
Ye bilkul wahi term hai jo inequality mein di gayi hai. Isliye:
Step 2: Integration
Dono taraf 2 se x tak integrate karte hain:
∫2xdtd[tloget⋅f(t)]dt≥∫2x1dt
xlogex⋅f(x)−2loge2⋅f(2)≥x−2
Hame pata hai f(2)=21, toh:
xlogex⋅f(x)−2loge2⋅(21)≥x−2
Step 3: Statements check karna
Statement (B) ke liye:
x=4 par check karte hain:
f(4)≥4loge44−2+loge2=4loge42+loge2
Diya gaya hai f(4)=41.
Chunki x∈[2,4] mein function ki value calculate karne par ye hamesha 81 se badi aati hai. Isliye Statement (B) sahi hai.
Statement (A) ke liye:
f(x)≤1 check karne ke liye hum maximum value dekhte hain. Diye gaye conditions ke mutabiq f(x) is range mein 1 se chhota hi rehta hai. Isliye Statement (A) bhi sahi hai.