Let a curve y=f(x),x∈(0,∞) pass through the points P(1,23) and Q(a,21). If the tangent at any point R(b,f(b)) to the given curve cuts the y-axis at the points S(0,c) such that bc=3, then (PQ)2 is equal to
Explanation

Equation of tangent y−f(b)=f′(b)(x−b)
Which passes through (0,c)
⇒c−f(b)=f′(b)(−b)
⇒b3−f(b)=f′(b)(−b)
⇒b2bf′(b)−f(b)=b3−3
⇒d(bf(b))=b3−3⇒bf(b)=2b23+λ
passes through (1,23)
⇒23=23+λ⇒λ=0
f(b)=2b3
f(a)=21⇒a=3
⇒Q(3,21)
PQ2=(3−1)2+(21−23)2
PQ2=22+(−1)2=4+1=5
Explanation

Equation of tangent y−f(b)=f′(b)(x−b)
Which passes through (0,c)
⇒c−f(b)=f′(b)(−b)
⇒b3−f(b)=f′(b)(−b)
⇒b2bf′(b)−f(b)=b3−3
⇒d(bf(b))=b3−3⇒bf(b)=2b23+λ
passes through (1,23)
⇒23=23+λ⇒λ=0
f(b)=2b3
f(a)=21⇒a=3
⇒Q(3,21)
PQ2=(3−1)2+(21−23)2
PQ2=22+(−1)2=4+1=5