NIMCET 2016 — Computer PYQ

6000 rpm $\equiv$ 6000 rotations per minute  

6000 rotations $\to$ 1 minute  

6000 rotations $\to$ 60 seconds  

1 rotation $\to \frac{60}{6000}=10^{-2}\text{s}$  

Average latency time = $\frac{1}{2}$ rotation  

Average latency time = $\frac{10^{-2}}{2}=\frac{10\times 10^{-3}}{2}=5\times 10^{-3}\text{s}$