Consider the equation (43)x=(y3)8 where x and y are unknown. The number of possible solution is
Explanation
Concept:
(ABCD)b=D∗b0+C∗b1+B∗b2+A∗b3
Calculation:
Given: (43)x=(y3)8
⇒3∗x0+4∗x1=3∗80+y∗81
⇒3+4x=3+8y
⇒4x=8y
∴x=2y
Now, y < 8 and x > 4 (because the number represented in base x is 43 or radix is always greater)
The following are possible solutions
y = 3,\, 4,\, 5,\, 6,\, 7 \,(y < 8)
x=6,8,10,12,14
Hence number of possible solution is five.
Explanation
Concept:
(ABCD)b=D∗b0+C∗b1+B∗b2+A∗b3
Calculation:
Given: (43)x=(y3)8
⇒3∗x0+4∗x1=3∗80+y∗81
⇒3+4x=3+8y
⇒4x=8y
∴x=2y
Now, y < 8 and x > 4 (because the number represented in base x is 43 or radix is always greater)
The following are possible solutions
y = 3,\, 4,\, 5,\, 6,\, 7 \,(y < 8)
x=6,8,10,12,14
Hence number of possible solution is five.