NIMCET 2018 — Mathematics PYQ
NIMCET | Mathematics | 2018Let f : R → R be defined by f(x) = {x+2∣x−2∣amp;if xamp;if x≥0lt;0. Find ∫−23f(x)dx.
Choose the correct answer:
- A.
0.5
- B.
2.5
- C.
4.5
(Correct Answer) - D.
6.5
4.5
Explanation
Concept:
- Definite Integral: If ∫f(x)dx=g(x)+C, then ∫abf(x)dx=[g(x)]ab=g(b)−g(a).
- If a ≤ c ≤ b, then ∫abf(x)dx=∫acf(x)dx+∫cbf(x)dx.
- ∫xndx=n+1xn+1+C.
Calculation:
Since the given function is a multi-valued function, let us separate the given definite integral into parts where the expressions of the function are different:
∫−23f(x)dx=∫−20f(x)dx+∫02f(x)dx+∫23f(x)dx
<br>=∫−20(x+2)dx+∫02(2−x)dx+∫23(x−2)dx
=[2x2+2x]−20+[2x−2x2]02+[2x2−2x]23
<br>=[0−(2−4)]+[4−2−0]+[29−6−(2−4)]
=2+2+29−4
<br>=4.5
Explanation
Concept:
- Definite Integral: If ∫f(x)dx=g(x)+C, then ∫abf(x)dx=[g(x)]ab=g(b)−g(a).
- If a ≤ c ≤ b, then ∫abf(x)dx=∫acf(x)dx+∫cbf(x)dx.
- ∫xndx=n+1xn+1+C.
Calculation:
Since the given function is a multi-valued function, let us separate the given definite integral into parts where the expressions of the function are different:
∫−23f(x)dx=∫−20f(x)dx+∫02f(x)dx+∫23f(x)dx
<br>=∫−20(x+2)dx+∫02(2−x)dx+∫23(x−2)dx
=[2x2+2x]−20+[2x−2x2]02+[2x2−2x]23
<br>=[0−(2−4)]+[4−2−0]+[29−6−(2−4)]
=2+2+29−4
<br>=4.5

