Tip:A–D to answerE for explanationV for videoS to reveal answer
∫x6(x5−x)1/5dx is equal to (where C is an arbitrary constant
- A.
(1−x21)4/5+C
- B.
(x4−x41)6/5+C
Correct Answer: 245(1−x41)6/5+C
Explanation
∫x6(x2−x)1/5dx
=∫x6x6(1−x41)1/5dx
Put 1−x41=t
x54dx=dt
41∫t1/5dt
=245t6/5+C
=245(1−x41)6/5+C
Explanation
∫x6(x2−x)1/5dx
=∫x6x6(1−x41)1/5dx
Put 1−x41=t
x54dx=dt
41∫t1/5dt
=245t6/5+C
=245(1−x41)6/5+C