Solution
Step 1: Simplify the first line equation.
The equation is r×a=b×a.
Rearranging terms:
If the cross product of two non-zero vectors is zero, they must be parallel. Therefore:
Substituting the given vectors:
Step 2: Simplify the second line equation.
The equation is r×b=a×b.
Rearranging terms:
Similarly, this implies:
Substituting the given vectors:
Step 3: Find the point of intersection.
At the point of intersection, the position vector r must be the same for both lines:
(2i^−k^)+λ(i^+j^)=(i^+j^)+μ(2i^−k^)
(2+λ)i^+λj^−k^=(1+2μ)i^+j^−μk^
Comparing the coefficients of i^,j^, and k^:
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For j^: λ=1
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For k^: −1=−μ⟹μ=1
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For i^: Check consistency ⟹2+λ=1+2μ
(The values are consistent).
Step 4: Calculate the coordinates.
Substitute λ=1 into the first line equation (or μ=1 into the second):
The coordinates of the point of intersection are (3,1,−1).
Final Answer:
The point of intersection is (3,1,−1).