IGDTUW 2026 — Reasoning PYQ

The correct option is (b) Monday.

Detailed Explanation:

Step 1: Calculate the total number of days in one year

According to the problem, the hypothetical calendar has:

• Number of months in a year = $10$

• Number of days in each month = $36$

$$\text{Total days in }1\text{ year}=10\times 36=360\text{ days}$$

Step 2: Determine the time gap between the two dates

We need to find the day for the $1^{\text{st}}$ day of the $3^{\text{rd}}$ month in the $3^{\text{rd}}$ year, starting from the $1^{\text{st}}$ day of the $3^{\text{rd}}$ month in the $1^{\text{st}}$ year.

The duration between these two specific dates is exactly $2$ full years:

$$\text{Total time gap}=2\text{ years}$$

$$\text{Total number of days}=2\times 360=720\text{ days}$$

Step 3: Find the number of odd days

A standard week consists of $7$ days. To find the shifting of the days, we divide the total number of days by $7$ to calculate the remaining odd days:

$$\frac{720}{7}=102\text{ weeks with a remainder of }6$$

$$\text{Number of odd days}=6$$

Step 4: Calculate the final day

We add the number of odd days to the initial day (Tuesday):

$$\text{Target Day}=\text{Tuesday}+6\text{ days}$$

Counting $6$ days forward from Tuesday gives Monday.