Explanation
Step 1: Understand the Behavior at Infinity
Let the limit of the function as x approaches infinity be a constant L. That is:
x→∞limf(x)=L
Since x→∞, the terms x+1 and x+2 will also approach infinity. Therefore, their limits will also be equal to L:
x→∞limf(x+1)=L
x→∞limf(x+2)=L
Step 2: Set up the Equation
Given the functional equation:
f(x)=31{f(x+1)+f(x+2)5}
Taking the limit as x→∞ on both sides:
L=31(L+L5)
Step 3: Solve for L
Multiply both sides by 3 to clear the fraction:
3L=L+L5
Subtract L from both sides:
2L=L5
Multiply both sides by L:
2L2=5
L2=25
Taking the square root on both sides:
L=±25
Step 4: Final Conclusion
Since the problem states that f(x) > 0 for all x∈R, the limit L must also be positive.
Therefore:
L=25
Correct Answer:
(b) 25