TEZPUR 2025 — Mathematics PYQ
TEZPUR | Mathematics | 2025The equation (a+1)2−2(a+1)=0 has:
Choose the correct answer:
- A.
two real roots
- B.
two real roots
(Correct Answer) - C.
one real root
- D.
no real roots
two real roots
Explanation
To find the roots of the equation, we can use the substitution method to simplify the quadratic expression.
1. Substitution:
Let x=(a+1). Substituting this into the equation:
x2−2x=0
2. Factorization:
Now, factor out the common term x:
x(x−2)=0
This gives us two possible values for x:
x=0orx=2
3. Back-substitution:
Now replace x with (a+1) to solve for a:
Case 1: a+1=0⟹a=−1
Case 2: a+1=2⟹a=1
4. Conclusion:
The equation has two distinct real roots, which are a=−1 and a=1.
The correct answer is that the equation has two real roots.
Explanation
To find the roots of the equation, we can use the substitution method to simplify the quadratic expression.
1. Substitution:
Let x=(a+1). Substituting this into the equation:
x2−2x=0
2. Factorization:
Now, factor out the common term x:
x(x−2)=0
This gives us two possible values for x:
x=0orx=2
3. Back-substitution:
Now replace x with (a+1) to solve for a:
Case 1: a+1=0⟹a=−1
Case 2: a+1=2⟹a=1
4. Conclusion:
The equation has two distinct real roots, which are a=−1 and a=1.
The correct answer is that the equation has two real roots.

