Five years ago, A was three times as old as B. Now, A is twice as old as B. What is A's current age (in years)?
Explanation
To solve this age-related problem from image_80937f.png, let us denote the current ages of A and B as A and B respectively.
1. Formulate the equations:
Based on the problem statement:
"Now, A is twice as old as B":
A=2B
"Five years ago, A was three times as old as B" (i.e., (A−5)=3(B−5)):
A−5=3(B−5)
2. Solve the system of equations:
Substitute the first equation (A=2B) into the second equation:
(2B)−5=3(B−5)
2B−5=3B−15
15−5=3B−2B
B=10
3. Find A's current age:
Now, substitute B=10 back into the first equation (A=2B):
A=2×10=20
Thus, A's current age is 20 years.
Correct Answer: Option 1