NIMCET 2026 — Computer PYQ

Q: How do I solve NIMCET 2026 Computer questions?

Practice NIMCET 2026 Computer previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Computer questions?

NIMCET Computer questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2026 — Computer PYQ

NIMCET | Computer | 2026

simplify the Boolean expression:

$(x + y^{'} + z^{'}) (x + y^{'} + z) (x + y + z^{'})$

Choose the correct answer:

Explanation

To simplify the expression, we use Boolean algebraic laws, specifically the distributive law $(A + B) (A + C) = A + B C$ :

1. Combine the first two terms:

$(x + y^{'} + z^{'}) (x + y^{'} + z) = (x + y^{'}) + (z^{'} \cdot z)$

Since $z^{'} \cdot z = 0$ , this simplifies to:

$(x + y^{'}) + 0 = x + y^{'}$

2. Multiply the result with the third term:

$(x + y^{'}) (x + y + z^{'})$

Distribute $(x + y^{'})$ over the second term:

$x (x + y + z^{'}) + y^{'} (x + y + z^{'})$

$= x + x y + x z^{'} + x y^{'} + y^{'} y + y^{'} z^{'}$

3. Apply simplification rules ( $x y + x = x$ , $y^{'} y = 0$ ):

$= x (1 + y + z^{'}) + x y^{'} + 0 + y^{'} z^{'}$

$= x + x y^{'} + y^{'} z^{'}$

$= x (1 + y^{'}) + y^{'} z^{'}$

$= x + y^{'} z^{'}$

The simplified Boolean expression is $x + y^{'} z^{'}$ .

Therefore, the correct option is (a).