Let be some entities. Statement a): All are . Statement b): No is a . Statement c): Every is a . Conclusions to evaluate: I. Some are . II. are not .

Only conclusion II follows Explanation: To solve this, we can represent the relationships between the entities as sets. Step 1: Formalize the Statements "All are " can be expressed as . "No is a " implies that the set of and the set of have no intersection: . "Every is a " can be expressed as . Step 2: Evaluate the Conclusions Evaluating Conclusion I ("Some are "): Since is a subset of , and has no overlap with , is also disjoint from . However, we know that is a subset of , but we do not know if intersects with . Therefore, "Some are " is not necessarily true because the relationship between and is undefined. Evaluating Conclusion II (" are not "): We know that all are contained within ( ). Since and are completely disjoint ( ), it is logically impossible for any to be an . Therefore, " are not " is a valid conclusion. Correct

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NIMCET 2026 — Reasoning PYQ

NIMCET | Reasoning | 2026

Let $W, X, Y, Z$ be some entities.

Statement a): All $Z s$ are $Y s$ .

Statement b): No $Y$ is a $X$ .

Statement c): Every $X$ is a $W$ .

Conclusions to evaluate:

I. Some $W s$ are $Z s$ .

II. $Z s$ are not $X s$ .

Choose the correct answer: