A takes twice as much time as B, or thrice as much time as C to finish a piece of work. Working together they can finish the work in 2 days. B can do the work alone in:
Explanation
Step 1: Express the time taken by each person
Let TB be the time taken by B to finish the work.
According to the problem:
Step 2: Determine individual work rates
The work rate is the reciprocal of the time taken. If the total work is 1 unit:
Work rate of A (RA) = 2TB1
Work rate of B (RB) = TB1
Work rate of C (RC) = 32TB1=2TB3
Step 3: Combine their work rates
When working together, their combined work rate is the sum of their individual rates. They finish the work in 2 days, so their combined rate is 21:
RA+RB+RC=21
2TB1+TB1+2TB3=21
Step 4: Solve for TB
Find a common denominator for the left side:
2TB1+2+3=21
2TB6=21
TB3=21
TB=6
Conclusion:
B can finish the work alone in 6 days. Therefore, the correct option is (b).