AMU 2026 — Mathematics PYQ
AMU | Mathematics | 2026The set of values of for which is

The set of values of x for which 1+tan3xtan2xtan3x−tan2x=1 is
ϕ
(Correct Answer){4π}
{nπ+4π,n=1,2,3,…}
{2nπ+4π,n=1,2,3,…}
ϕ
The given equation features an expression on the left-hand side that directly matches the standard tangent subtraction formula:
tan(A−B)=1+tanAtanBtanA−tanB
By setting A=3x and B=2x, the equation simplifies significantly:
tan(3x−2x)=1
tanx=1
The principal solution where tanx=1 occurs at x=4π. Therefore, the standard general solution for the tangent function is given by:
x=nπ+4π,where n∈Z
Before finalizing the solution, any values of x that make the individual components of the original equation undefined must be excluded. The original expression contains terms for tan3x and tan2x.
The tangent function tanθ becomes undefined when its argument is an odd multiple of 2π:
θ=(2k+1)2π,k∈Z
Let's test our general solution x=nπ+4π for the term tan2x:
Substitute x=nπ+4π into 2x:
2x=2(nπ+4π)
2x=2nπ+2π
2x=(4n+1)2π
Since (4n+1) is always an odd integer for any integer value of n, the angle 2x will always land exactly on an odd multiple of 2π.
Consequently:
tan2x=tan((4n+1)2π)=±∞(Undefined)
Because the expression tan2x is completely undefined for every single value produced by our general solution formula, there are no permissible values of x that can satisfy the original mathematical statement.
Thus, the solution set is empty, which is denoted by the null set symbol ϕ.
This directly matches option (a).
The given equation features an expression on the left-hand side that directly matches the standard tangent subtraction formula:
tan(A−B)=1+tanAtanBtanA−tanB
By setting A=3x and B=2x, the equation simplifies significantly:
tan(3x−2x)=1
tanx=1
The principal solution where tanx=1 occurs at x=4π. Therefore, the standard general solution for the tangent function is given by:
x=nπ+4π,where n∈Z
Before finalizing the solution, any values of x that make the individual components of the original equation undefined must be excluded. The original expression contains terms for tan3x and tan2x.
The tangent function tanθ becomes undefined when its argument is an odd multiple of 2π:
θ=(2k+1)2π,k∈Z
Let's test our general solution x=nπ+4π for the term tan2x:
Substitute x=nπ+4π into 2x:
2x=2(nπ+4π)
2x=2nπ+2π
2x=(4n+1)2π
Since (4n+1) is always an odd integer for any integer value of n, the angle 2x will always land exactly on an odd multiple of 2π.
Consequently:
tan2x=tan((4n+1)2π)=±∞(Undefined)
Because the expression tan2x is completely undefined for every single value produced by our general solution formula, there are no permissible values of x that can satisfy the original mathematical statement.
Thus, the solution set is empty, which is denoted by the null set symbol ϕ.
This directly matches option (a).