AMU 2026 — Computer PYQ

Since the problem states that all are integer values, any division operation performed will be integer division (where the fractional part is discarded).

Given initial values:

• $$i=7$$

• $$j=8$$

• $$k=6$$

Let's evaluate the expression by following the rules of operator precedence (innermost parentheses first):

$$\text{Expression: }i=((i\%4)\ast (7+(j-2)/(k+1)))$$

Step 1: Evaluate the individual inner parentheses

• Substitute the values into the sub-expressions:

  • $$(i\%4)⟹(7\%4)=3$$

    (Remainder when 7 is divided by 4)

  • $$(j-2)⟹(8-2)=6$$

  • $$(k+1)⟹(6+1)=7$$

Step 2: Substitute these values back into the main expression

$$i=(3\ast (7+6/7))$$

Step 3: Evaluate the division inside the right parenthesis

• According to operator precedence, division (

  $$/$$

  ) is performed before addition (

  $$+$$

  ).

• Since this is integer division:

  $$6/7=0$$

Step 4: Evaluate the addition inside the parenthesis

$$i=(3\ast (7+0))$$

$$i=(3\ast 7)$$

Step 5: Final multiplication

$$i=21$$

Therefore, the final value of $i$ is 21.