Let be an array of numbers consisting of sequence of 's followed by a sequence of 's. The problem is to find the smallest index that is by probing the minimum numbers of locations in . The worst case number of probes performed by an optimal algorithm is

5 Explanation: Understand the Nature of the Array: The array is sorted implicitly because it consists entirely of a block of 's followed directly by a block of 's (e.g., ). Finding the smallest index where is equivalent to finding the transition point or the first occurrence of . Identify the Optimal Strategy: Since the array structure is monotonically ordered ( ), the optimal algorithm to search for this transition point with the minimum number of probes is Binary Search . Worst-Case Probing Analysis: For an array of size , binary search systematically divides the search space in half with each probe. The maximum number of comparisons (or probes) required in the absolute worst-case scenario to pin down a single transition index is given by the formula: (Alternatively written as ) Substitute the Given Va

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AMU 2026 — Computer PYQ

AMU | Computer | 2026

Let $A$ be an array of $31$ numbers consisting of sequence of $0$ 's followed by a sequence of $1$ 's. The problem is to find the smallest index $i$ that $A [i]$ is $1$ by probing the minimum numbers of locations in $A$ . The worst case number of probes performed by an optimal algorithm is

AMU 2026 — Computer PYQ

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