Explanation
1. Conceptual Framework
To write a physical law in a covariant form (independent of the choice of reference frame), all quantities in the equation must change properly under Lorentz transformations. This requires expressing the mechanics using tensors and four-vectors with respect to proper time (τ) rather than coordinate time (t).
Four-momentum (pμ): Represents the relativistic energy and momentum vector.
Four-velocity (Uμ or Uν): The rate of change of position four-vector with respect to proper time (τ).
Electromagnetic Field Tensor (Fμν): A rank-2 antisymmetric tensor containing both electric and magnetic field components.
Proper Time (τ): An invariant scalar denoting time measured in the particle's rest frame.
2. Analysis of the Relativistic Lorentz Force
The classical Lorentz force equation is given by:
F=q(E+v×B)
In Minkowski space, this expression generalizes to a relation connecting the Minkowski four-force (Kμ), the electromagnetic field tensor (Fμν), and the four-velocity.
The four-force is defined as the derivative of four-momentum with respect to proper time τ:
Kμ=dτdpμ
The interaction with the electromagnetic field tensor requires a contracted index matching to yield a clean four-vector result:
Kμ=qFμνUν
3. Evaluating the Indices and Options
Let's break down why option (a) is structurally and physically valid:
Time Parameter: It must use proper time (dτ) instead of coordinate time (dt) to maintain full manifest covariance. This immediately eliminates choices (b) and (d).
Index Balance: The left side has a free contravariant index μ. Therefore, the right side must also feature a free contravariant index μ.
In the term FμνUν, the index ν is repeated (once as a superscript in F and once as a subscript in U). This means ν is a dummy index summed over all four dimensions (0,1,2,3) following the Einstein summation convention.
This leaves μ as the lone free index on both sides, ensuring consistent tensor transformation balance. In choice (c), the indices are improperly matched.
Thus, the exact tensor formulation matches option (a).
Correct Answer
The correct option is (a) dτdpμ=qFμνUν.