How do I solve JAMIA 2026 Mathematics questions?

Practice JAMIA 2026 Mathematics previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

What is the difficulty level of JAMIA Mathematics questions?

JAMIA Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Are JAMIA previous year papers available for free?

Yes. Mathem Solvex provides free access to JAMIA previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Tip:A–D to answerE for explanationV for videoS to reveal answer

JAMIA 2026 — Mathematics PYQ

JAMIA | Mathematics | 2026

If $1! 2! 3! am p; 2! am p; 3! am p; 4! am p; 3! am p; 4! am p; 5! = x$ , then value of $x$ is ________

Choose the correct answer:

Explanation

Step 1: Expand the factorials to find common factors

Let's rewrite the elements of each row to highlight the common factors:

Row 1 ( $R_{1}$ ): $1!, 2 \cdot 1!, 3 \cdot 2 \cdot 1!$
Row 2 ( $R_{2}$ ): $2!, 3 \cdot 2!, 4 \cdot 3 \cdot 2!$
Row 3 ( $R_{3}$ ): $3!, 4 \cdot 3!, 5 \cdot 4 \cdot 3!$

Now, take out common factors from each row:

Take out $1!$ from Row 1 ( $R_{1}$ )
Take out $2!$ from Row 2 ( $R_{2}$ )
Take out $3!$ from Row 3 ( $R_{3}$ )

$Δ = (1! \times 2! \times 3!) 111 am p; 2 am p; 3 am p; 4 am p; 6 am p; 12 am p; 20$

Since $1! = 1$ , $2! = 2$ , and $3! = 6$ :

$Δ = (1 \times 2 \times 6) 111 am p; 2 am p; 3 am p; 4 am p; 6 am p; 12 am p; 20 = 12 111 am p; 2 am p; 3 am p; 4 am p; 6 am p; 12 am p; 20$

Step 2: Apply row operations to simplify

To make the evaluation easy, let's create zeros in the first column using row transformations:

Perform $R_{2} \to R_{2} - R_{1}$
Perform $R_{3} \to R_{3} - R_{1}$

$Δ = 12 1 1 - 1 1 - 1 am p; 2 am p; 3 - 2 am p; 4 - 2 am p; 6 am p; 12 - 6 am p; 20 - 6$

$Δ = 12 100 am p; 2 am p; 1 am p; 2 am p; 6 am p; 6 am p; 14$

Step 3: Evaluate the simplified determinant

Expanding along the first column ( $C_{1}$ ):

$Δ = 12 \times 1 \cdot 12 am p; 6 am p; 14$

$Δ = 12 \times ((1 \times 14) - (6 \times 2))$

$Δ = 12 \times (14 - 12)$

$Δ = 12 \times 2 = 24$

Step 4: Match the answer with the given choices

Now, let's check the factorial values of the options:

(a) $2! = 2$
(b) $3! = 6$
(c) $4! = 4 \times 3 \times 2 \times 1 = 24$
(d) $5! = 120$

Since our calculated value of $x$ is $24$ , it corresponds to $4!$ .

Correct Answer:

(c) 4!