JAMIA 2026 — Mathematics PYQ
JAMIA | Mathematics | 2026How many reflexive relations are possible on the set ?

How many reflexive relations are possible on the set A={1,2,3,4}?
4
2048
1024
4096
(Correct Answer)4096
A relation R on a set A is called reflexive if every element in A is related to itself.
Mathematically, for every element a∈A, the ordered pair (a,a) must belong to the relation R.
Given the set A={1,2,3,4}, the total number of elements is:
n=4
The total number of ordered pairs in the Cartesian product A×A is given by n×n=n2.
For our set, 42=16 total ordered pairs. These 16 pairs can be divided into two separate types:
Diagonal Elements (Reflexive pairs): Pairs where the first element equals the second element, i.e., (a,a).
Examples: {(1,1),(2,2),(3,3),(4,4)}
Total diagonal elements =n=4
Non-Diagonal Elements: Pairs where the first element does not equal the second element, i.e., (a,b) where a=b.
Examples: (1,2),(2,1),(3,4), etc.
Total non-diagonal elements =n2−n=16−4=12
When forming a reflexive relation, we must make a binary choice (either include or exclude) for each ordered pair:
For the diagonal elements, there is only 1 choice for each pair: they must be included to keep the relation reflexive.
For the non-diagonal elements, there are 2 choices for each pair: they can either be included or excluded from the relation.
Using the fundamental counting principle:
Total Reflexive Relations=(Choices for Diagonal Pairs)×(Choices for Non-Diagonal Pairs)
Total Reflexive Relations=(1)n×(2)n2−n=2n2−n
Now, substitute the value of n=4 into our derived formula:
Total Reflexive Relations=242−4
Total Reflexive Relations=216−4
Total Reflexive Relations=212
Let's compute the value of 212:
210=1024
211=2048
212=4096
The total number of possible reflexive relations on the set A is 4096.
Therefore, the correct option is (d).
A relation R on a set A is called reflexive if every element in A is related to itself.
Mathematically, for every element a∈A, the ordered pair (a,a) must belong to the relation R.
Given the set A={1,2,3,4}, the total number of elements is:
n=4
The total number of ordered pairs in the Cartesian product A×A is given by n×n=n2.
For our set, 42=16 total ordered pairs. These 16 pairs can be divided into two separate types:
Diagonal Elements (Reflexive pairs): Pairs where the first element equals the second element, i.e., (a,a).
Examples: {(1,1),(2,2),(3,3),(4,4)}
Total diagonal elements =n=4
Non-Diagonal Elements: Pairs where the first element does not equal the second element, i.e., (a,b) where a=b.
Examples: (1,2),(2,1),(3,4), etc.
Total non-diagonal elements =n2−n=16−4=12
When forming a reflexive relation, we must make a binary choice (either include or exclude) for each ordered pair:
For the diagonal elements, there is only 1 choice for each pair: they must be included to keep the relation reflexive.
For the non-diagonal elements, there are 2 choices for each pair: they can either be included or excluded from the relation.
Using the fundamental counting principle:
Total Reflexive Relations=(Choices for Diagonal Pairs)×(Choices for Non-Diagonal Pairs)
Total Reflexive Relations=(1)n×(2)n2−n=2n2−n
Now, substitute the value of n=4 into our derived formula:
Total Reflexive Relations=242−4
Total Reflexive Relations=216−4
Total Reflexive Relations=212
Let's compute the value of 212:
210=1024
211=2048
212=4096
The total number of possible reflexive relations on the set A is 4096.
Therefore, the correct option is (d).