If the base of a right-angled triangle is doubled, what should happen to its height so that the area remains unchanged?
Explanation
Step 1: Formula for the area of a triangle
The standard formula to calculate the area (A) of a right-angled triangle with base (b) and height (h) is:
A=21×b×h
Step 2: Set up the conditions for the new triangle
Let the initial parameters of the triangle be:
Initial Base = b
Initial Height = h
Initial Area = A1=21bh
According to the question, the new parameters are modified as follows:
Step 3: Equate the initial area to the new area
The problem states that the total area must remain unchanged, which mathematically means A2=A1:
21×b′×h′=21×b×h
Substitute b′=2b into the equation:
21×(2b)×h′=21×b×h
Step 4: Solve for the new height (h′)
Cancel out the common term 21 from both sides:
2b×h′=b×h
Now, divide both sides by b (assuming b=0):
2h′=h
h′=21h
Conclusion:
To keep the area constant when the base is doubled, the height must be multiplied by a factor of 21 (i.e., it must be halved).
Correct Answer
The correct option is (a) 1/2.