X, Y, and Z together can complete a work in 6 days. X alone takes 12 days and Y alone takes 18 days to complete the same work. In how many days will X and Z together complete this work?
Explanation
Method 1: The LCM (Total Work) Method
1. Find the Total Work:
Let the total work be the Least Common Multiple (LCM) of the given number of days (6, 12, and 18).
Total Work=LCM(6,12,18)=36 units
2. Calculate individual efficiencies (work done per day):
Efficiency of (X+Y+Z)=636=6 units/day
Efficiency of X=1236=3 units/day
Efficiency of Y=1836=2 units/day
3. Find the efficiency of Z:
Efficiency of Z=Efficiency of (X+Y+Z)−(Efficiency of X+Efficiency of Y)
Efficiency of Z=6−(3+2)=6−5=1 unit/day
4. Find the combined efficiency of X and Z:
Efficiency of (X+Z)=Efficiency of X+Efficiency of Z
Efficiency of (X+Z)=3+1=4 units/day
5. Calculate the time taken by X and Z together:
Days taken by (X+Z)=Efficiency of (X+Z)Total Work
Days taken by (X+Z)=436=9 days
Correct Answer
The correct option is (d) 9.