NIMCET 2007 — Reasoning PYQ
NIMCET | Reasoning | 2007The chances of throwing up a number that is greater than , and in that order in throws of dices simultaneously is:

The chances of throwing up a number that is greater than , and in that order in throws of dices simultaneously is:
When two unbiased six-sided dice are rolled simultaneously, the total number of possible outcomes is given by:
Let the three independent throws be represented by events , , and , respectively. We need to find the probability of all three events happening sequentially in that specific order:
The possible sums greater than are and . Let's list the favorable outcomes for each sum:
Sum = 9: outcomes
Sum = 10: outcomes
Sum = 11: outcomes
Sum = 12: outcome
Instead of counting all outcomes greater than , it is much quicker to find the outcomes where the sum is less than or equal to and subtract it from :
Sum = 2: outcome
Sum = 3: outcomes
Sum = 4: outcomes
Sum = 5: outcomes
The possible sums greater than are and :
Sum = 11: outcomes
Sum = 12: outcome
Since each throw of the pair of dice is an independent event, we multiply the individual probabilities together:
The correct option is (d) 65/3888