NIMCET 2007 Mathematics PYQ — Numerical value of the expression for is:… | Mathem Solvex | Mathem Solvex
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NIMCET 2007 — Mathematics PYQ
NIMCET | Mathematics | 2007
Numerical value of the expression 2x2+23x3+1 for x=−3 is:
Choose the correct answer:
A.
4
(Correct Answer)
B.
2
C.
3
D.
0
Correct Answer:
4
Explanation
Step 1: Understand the Absolute Value Property
The expression contains an absolute value sign ∣⋅∣, which means whatever value we get inside the bars, the final output will be its non-negative (positive) magnitude:
∣−k∣=kand∣k∣=k
Step 2: Substitute x=−3 into the Expression
Let's substitute x=−3 into the given algebraic fraction:
E=2(−3)2+23(−3)3+1
Step 3: Evaluate the Numerator and Denominator
Evaluate the Numerator:
Calculate the cube of −3:
(−3)3=−3×−3×−3=−27
Multiply by 3 and add 1:
3(−27)+1=−81+1=−80
Evaluate the Denominator:
Calculate the square of −3:
(−3)2=−3×−3=9
Multiply by 2 and add 2:
2(9)+2=18+2=20
Step 4: Divide the Values and Apply Absolute Value
Substitute the calculated numerator and denominator back into the expression:
E=20−80
Simplify the fraction inside the bars:
E=∣−4∣
Apply the absolute value property to get the positive numerical value:
E=4
Conclusion
The numerical value of the expression for x=−3 is 4.
Correct Option:(a) 4
Explanation
Step 1: Understand the Absolute Value Property
The expression contains an absolute value sign ∣⋅∣, which means whatever value we get inside the bars, the final output will be its non-negative (positive) magnitude:
∣−k∣=kand∣k∣=k
Step 2: Substitute x=−3 into the Expression
Let's substitute x=−3 into the given algebraic fraction:
E=2(−3)2+23(−3)3+1
Step 3: Evaluate the Numerator and Denominator
Evaluate the Numerator:
Calculate the cube of −3:
(−3)3=−3×−3×−3=−27
Multiply by 3 and add 1:
3(−27)+1=−81+1=−80
Evaluate the Denominator:
Calculate the square of −3:
(−3)2=−3×−3=9
Multiply by 2 and add 2:
2(9)+2=18+2=20
Step 4: Divide the Values and Apply Absolute Value
Substitute the calculated numerator and denominator back into the expression:
E=20−80
Simplify the fraction inside the bars:
E=∣−4∣
Apply the absolute value property to get the positive numerical value:
E=4
Conclusion
The numerical value of the expression for x=−3 is 4.