To find the minimum number of gates, we must first simplify the expression using Boolean algebra laws, specifically De Morgan's Law.
Step 1: Simplify the complemented term
Let’s focus on the second part of the expression: P=(zˉ+x+y)(xˉ+yˉ).
Using De Morgan's Law (A⋅B=Aˉ+Bˉ):
Now apply De Morgan's Law again to the individual parts (A+B+C=AˉBˉCˉ):
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(zˉ+x+y)=zxˉyˉ
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(xˉ+yˉ)=xy
So, the second part P becomes:
Step 2: Combine with the first part of the function
Now substitute P back into the original function f(x,y,z):
Step 3: Factor and simplify
Group the terms involving z:
Using the identity (x+y+xˉyˉ)=(x+y+x+y). We know that A+Aˉ=1. Here A=(x+y).
Therefore:
The expression simplifies to:
Step 4: Count the gates
The simplified function is f=z+xy.
To implement this:
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One AND gate is needed for the product xy.
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One OR gate is needed to add z to the result of xy.
Total number of gates = 2.
Final Answer:
The correct option is (a) 2.