NIMCET 2008 — Computer PYQ

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Question

NIMCET 2008 — Computer PYQ

NIMCET | Computer | 2008

The capacity of a memory units is defined by the number of words multipled by the number of bits per word. How many seperate address and data line are needed for a memory of 4𝐾×16?

Choose the correct answer:

Explanation

A memory configuration is usually represented as $M \times N$ , where $M$ is the number of words (locations) and $N$ is the number of bits per word.

1. Finding Data Lines

The number of data lines is always equal to the number of bits stored in each word ( $N$ ).

In $4K \times 16$ , the number of bits per word is 16.

$\text{Data Lines} = 16$

2. Finding Address Lines

The number of address lines ( $n$ ) is determined by the total number of words ( $M$ ) using the formula:

M = 2^n

Given $M = 4K$ :

We know that $1K = 1024 = 2^{10}$
So, $4K = 4 \times 1024 = 4096$
Expressing 4096 as a power of 2:

$4096 = 2^2 \times 2^{10} = 2^{12}$

Comparing $2^{12}$ with $2^n$ , we get:

\text{Address Lines (n)} = 12

Conclusion:

To access a $4K \times 16$ memory, we need 12 address lines to select the specific word and 16 data lines to carry the content of that word.

Correct Option: (c) 12 address lines and 16 data lines