NIMCET 2008 — Reasoning PYQ

Q: How do I solve NIMCET 2008 Reasoning questions?

Practice NIMCET 2008 Reasoning previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Reasoning questions?

NIMCET Reasoning questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2008 — Reasoning PYQ

NIMCET | Reasoning | 2008

Larger, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships. 3 medium ships carry the same amount of water as 2 larger ships and 1 small ship. 15 large, 7 medium and 14 small ships, each made 36 journeys and brought a certain quantity of water. In how many journeys would 12 large, 14 medium and 21 small ships bring the same quantity of water?

Choose the correct answer:

Explanation

Let the capacity of a Large ship be $L$ , Medium ship be $M$ , and Small ship be $S$ .

Step 1: Establish the relationships between ship capacities.

From the first condition:

4L = 7S \implies L = \frac{7}{4}S

From the second condition:

3M = 2L + 1S

Substitute the value of $L$ in terms of $S$ :

3M = 2\left(\frac{7}{4}S\right) + 1S

3M = \frac{7}{2}S + S = \frac{9}{2}S

M = \frac{9}{6}S = \frac{3}{2}S

So, we have the ratios:

$L = 1.75S$
$M = 1.5S$
$S = 1S$

Step 2: Calculate the total water brought in the first scenario.

The fleet consists of 15 Large, 7 Medium, and 14 Small ships. Total capacity per journey in terms of $S$ :

Total\_Cap_1 = 15L + 7M + 14S

Total\_Cap_1 = 15(1.75S) + 7(1.5S) + 14S

Total\_Cap_1 = 26.25S + 10.5S + 14S = 50.75S

Since they made 36 journeys, the Total Water is:

W = 50.75S \times 36

Step 3: Calculate the capacity of the second fleet.

The second fleet consists of 12 Large, 14 Medium, and 21 Small ships.

Total\_Cap_2 = 12L + 14M + 21S

Total\_Cap_2 = 12(1.75S) + 14(1.5S) + 21S

Total\_Cap_2 = 21S + 21S + 21S = 63S

Step 4: Find the number of journeys ( $n$ ).

Since the total water $W$ remains the same:

63S \times n = 50.75S \times 36

n = \frac{50.75 \times 36}{63}

n = \frac{50.75 \times 4}{7}

n = 7.25 \times 4 = 29

Final Answer:

The second fleet would require 29 journeys.

Correct Option: (c) 29