NIMCET 2008 — Reasoning PYQ

1. Identify the Middle Term

There are seven consecutive integers. The problem states that $Q$ is the middle term.

• Sequence position: $1,2,3,\mathbf{Q},5,6,7$

• In all options, $Q$ is at the 4th position.

2. Analyze the "Difference" Constraint

The statement "$U$ is as much less than $Q$ as $R$ is greater than $S$" translates to the equation:

Rearranging this:

3. Analyze the "P and S" Constraint

$P$ is 3 greater than $S$:

This means there must be exactly two letters between $S$ and $P$ in the sequence (e.g., $S,\_,\_,P$).

4. Evaluating the Options

• Option (a) $PVSQRTU$:

  • $S$ is at pos 3, $P$ is at pos 1. $P$ is less than $S$. (Incorrect)

• Option (b) $SUTQPRV$:

  • $S$ is at pos 1, $P$ is at pos 5. $P-S=4$. But the rule says $P-S=3$. (Incorrect)

• Option (c) $USVQPRT$:

  • $S$ is at pos 2, $P$ is at pos 5. $P-S=3$. (Possible)

  • Let's check $Q-U=R-S$:

    • $Q$ is pos 4, $U$ is pos 1 $\Rightarrow 4-1=3$

    • $R$ is pos 6, $S$ is pos 2 $\Rightarrow 6-2=4$

  • $3\ne 4$. (Incorrect)

• Option (d) $TUSQPRV$:

  • $S$ is at pos 3, $P$ is at pos 6. $P-S=3$. (Matches)

  • Let's check $Q-U=R-S$:

    • $Q$ is pos 4, $U$ is pos 2 $\Rightarrow 4-2=2$

    • $R$ is pos 5, $S$ is pos 3 $\Rightarrow 5-3=2$

  • $2=2$. (Matches)

  • $V$ is greater than $U$: $V$ is pos 7, $U$ is pos 2. (Matches)

Final Answer:

The correct sequence from lowest to highest value is (d) $TUSQPRV$.