1. Analyze the Letters:
The word is INDIA.
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Total letters: 5
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Repeated letters: I appears 2 times.
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Letters in alphabetical order: A, D, I, I, N
2. Finding words starting with 'A':
If 'A' is fixed at the first position, we arrange the remaining letters (D, I, I, N):
Number of words=2!4!=224=12
(Total count so far: 12)
3. Finding words starting with 'D':
If 'D' is fixed at the first position, we arrange the remaining letters (A, I, I, N):
Number of words=2!4!=224=12
(Total count so far: 12 + 12 = 24)
4. Finding words starting with 'I':
If 'I' is fixed at the first position, we arrange the remaining letters (A, D, I, N). Since only one 'I' remains, there are no duplicates to divide by:
(Total count so far: 24 + 24 = 48)
5. Finding words starting with 'N':
We need the 58th word. We have reached 48. We need 10 more words starting with 'N'.
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Words starting with 'NA': Fix 'N' and 'A', arrange (D, I, I):
(Total count: 48 + 3 = 51)
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Words starting with 'ND': Fix 'N' and 'D', arrange (A, I, I):
(Total count: 51 + 3 = 54)
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Words starting with 'NI': Fix 'N' and 'I', arrange (A, D, I):
Final Answer:
The 58th word is NIDIA.
Correct Option: (c)
