NIMCET 2009 — Reasoning PYQ

To find the sum of all $n$-digit numbers formed using $n$ distinct digits, we use a standard mathematical formula.

1. Identify the given values:

• Given digits: $1,2,5,8$

• Number of digits ($n$): $4$

• Sum of the given digits: $1+2+5+8=16$

2. Formula for the sum of all possible numbers:

The sum of all numbers formed by using $n$ non-zero distinct digits is:

3. Apply the formula:

For $n=4$, the formula becomes:

Since $3!=3\times 2\times 1=6$:

4. Final Calculation:

Conclusion:

The calculated sum, 106,656, falls clearly between 100,000 and 150,000.

Correct Option:

(d) 100000 and 150000