How many pairs of letters are there in the word ‘PRISON’, each of which has as many letters between its two letters in the word as there are between them in the English alphabet?
Explanation
Step 1: Assign positions to the letters
The word is PRISON.
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P = 16
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R = 18
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I = 9
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S = 19
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O = 15
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N = 14
Step 2: Check Forward Direction
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P (16): Count forward: 17(R), 18(I), 19(S). (P and S) is a pair because there are 2 letters between them in the word and in the alphabet.
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R (18): Count forward: 19(I), 20(S)... No match.
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I (9): Count forward: 10(S), 11(O), 12(N). No match.
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S (19): Count forward: 20(O), 21(N). No match.
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O (15): Count forward: 16(N). No match.
Step 3: Check Backward Direction
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N (14): Count backward: 15(O). (N and O) is a pair (14, 15).
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N (14): Count backward further: 16(S), 17(I), 18(R). (N and R) is a pair because there are 3 letters between them (N,O,S,I,R).
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O (15): Count backward: 16(S), 17(I), 18(R). (O and R) is a pair because there are 2 letters between them (O,S,I,R).
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S (19): Count backward: 20, 21, 22. No match.
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I (9): Count backward: 10, 11. No match.
Step 4: List the identified pairs
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P - S (Forward)
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N - O (Backward)
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N - R (Backward)
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O - R (Backward)
There are a total of 4 such pairs.
Correct Option: (c)
