1. Use the Property of Odd Functions
We know that sin−1(−x)=−sin−1x. Substituting this into the given equation:
sin−1x+cos−1(1−x)=−sin−1x
2. Rearrange the Equation
Move all sin−1x terms to one side:
cos−1(1−x)=−sin−1x−sin−1x
3. Apply Trigonometric Functions to Both Sides
Take the cosine of both sides:
cos(cos−1(1−x))=cos(−2sin−1x)
Using the property cos(cos−1θ)=θ and the fact that cosine is an even function (cos(−θ)=cosθ):
4. Use the Double Angle Formula
Recall the identity cos(2θ)=1−2sin2θ. Let θ=sin−1x, which implies sinθ=x.
Substituting this into the identity:
5. Form the Quadratic Equation
Simplify the resulting equation:
6. Compare with Options
The equation we derived is 2x2−x=0.
Looking at the provided options:
Since 2x2−x=0 does not match any of the first three options exactly, we select the "None of these" category.
Final Answer:
The correct option is (d) None of these.