NIMCET 2009 — Mathematics PYQ
NIMCET | Mathematics | 2009The vector B=3i^+4k^ is to be written as the sum of a vector B1 parallel to A=i^+j^ and a vector B2 perpendicular to A, then B1 is:
Choose the correct answer:
- A.
23(i^+j^)
(Correct Answer) - B.
32(i^+j^)
23(i^+j^)
Explanation
1. Given Data:
-
Vector B=3i^+0j^+4k^
-
Vector A=i^+j^+0k^
-
B=B1+B2
-
B1∥A and B2⊥A
2. Formula for Parallel Component (B1):
The projection of B onto A is given by:
3. Step-by-Step Calculation:
-
Calculate the dot product (B⋅A):
B⋅A=(3)(1)+(0)(1)+(4)(0)B⋅A=3+0+0=3 -
Calculate the magnitude squared of A (∣A∣2):
∣A∣2=(1)2+(1)2+(0)2∣A∣2=1+1=2 -
Find B1:
B1=(23)AB1=23(i^+j^)
Final Answer:
The vector B1 is 23(i^+j^). the correct option is (a).
Explanation
1. Given Data:
-
Vector B=3i^+0j^+4k^
-
Vector A=i^+j^+0k^
-
B=B1+B2
-
B1∥A and B2⊥A
2. Formula for Parallel Component (B1):
The projection of B onto A is given by:
3. Step-by-Step Calculation:
-
Calculate the dot product (B⋅A):
B⋅A=(3)(1)+(0)(1)+(4)(0)B⋅A=3+0+0=3 -
Calculate the magnitude squared of A (∣A∣2):
∣A∣2=(1)2+(1)2+(0)2∣A∣2=1+1=2 -
Find B1:
B1=(23)AB1=23(i^+j^)
Final Answer:
The vector B1 is 23(i^+j^). the correct option is (a).
