NIMCET 2015 — Mathematics PYQ
NIMCET | Mathematics | 2015If A+B+C=π, then the value of sin(A+B+C)−sinBcos(A+B)amp;sinBamp;0amp;−tanAamp;cosCamp;tanAamp;0 is:
Choose the correct answer:
- A.
0
(Correct Answer) - B.
1
- C.
2sinAsinB
- D.
2
0
Explanation
1. Simplify the Trigonometric Terms
Given A+B+C=π:
-
sin(A+B+C)=sin(π)=0
-
Since A+B=π−C, then cos(A+B)=cos(π−C)=−cosC
2. Substitute the simplified values into the determinant
Let the determinant be Δ:
3. Identify the Matrix Property
Observe the structure of the matrix M corresponding to this determinant:
Notice that the diagonal elements are all 0, and for any element aij, we have aij=−aji.
For example:
-
a12=sinB and a21=−sinB
-
a13=cosC and a31=−cosC
-
a23=tanA and a32=−tanA
This is a Skew-Symmetric Matrix.
4. Apply the Property of Skew-Symmetric Determinants
The determinant of a skew-symmetric matrix of odd order (in this case, 3×3) is always zero.
Alternatively, by direct expansion along the first row:
Correct Option: (a)
Explanation
1. Simplify the Trigonometric Terms
Given A+B+C=π:
-
sin(A+B+C)=sin(π)=0
-
Since A+B=π−C, then cos(A+B)=cos(π−C)=−cosC
2. Substitute the simplified values into the determinant
Let the determinant be Δ:
3. Identify the Matrix Property
Observe the structure of the matrix M corresponding to this determinant:
Notice that the diagonal elements are all 0, and for any element aij, we have aij=−aji.
For example:
-
a12=sinB and a21=−sinB
-
a13=cosC and a31=−cosC
-
a23=tanA and a32=−tanA
This is a Skew-Symmetric Matrix.
4. Apply the Property of Skew-Symmetric Determinants
The determinant of a skew-symmetric matrix of odd order (in this case, 3×3) is always zero.
Alternatively, by direct expansion along the first row:
Correct Option: (a)