NIMCET 2012 — Reasoning PYQ

Q: How do I solve NIMCET 2012 Reasoning questions?

Practice NIMCET 2012 Reasoning previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Reasoning questions?

NIMCET Reasoning questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2012 — Reasoning PYQ

NIMCET | Reasoning | 2012

In a certain year, there were exactly four Fridays and four Mondays in January. On what day of the week did the $20^{th}$ of January fall that year?

Choose the correct answer:

Explanation

Step 1: Identify which days occur 5 times

The problem states there are exactly four Fridays and four Mondays.

This implies that neither Friday nor Monday can fall on the $1^{st}, 2^{nd},$ or $3^{rd}$ of January.

Step 2: Determine the sequence of days

Let's look at the days between Monday and Friday: Tuesday, Wednesday, and Thursday.

If these three days are the ones that occur 5 times, then:

$1^{st}$ January = Tuesday
$2^{nd}$ January = Wednesday
$3^{rd}$ January = Thursday

If the $1^{st}$ is a Tuesday, then the $31^{st}$ (last day) will also be a Thursday ( $1 + 30 \text{ days}$ , where $30 \div 7$ leaves a remainder of $2$ , so Tuesday $+ 2 = \text{Thursday}$ ). In this scenario:

Mondays: $7, 14, 21, 28$ (Total 4) — Matches condition.
Fridays: $4, 11, 18, 25$ (Total 4) — Matches condition.

Step 3: Calculate the $20^{th}$ of January

Since the $1^{st}$ of January is a Tuesday:

$1^{st}$ = Tuesday
$8^{th}$ = Tuesday
$15^{th}$ = Tuesday
$15 + 5 = 20^{th}$
Tuesday $+ 5 \text{ days} = \mathbf{Sunday}$

Conclusion:

The $20^{th}$ of January falls on a Sunday.

Correct Option: (b)