NIMCET 2012 — Reasoning PYQ

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Question

NIMCET 2012 — Reasoning PYQ

NIMCET | Reasoning | 2012

Directions : Read the following passage carefully and answer the questions.
Six boys A, B, C, D, E and F are marching in a line. They are arranged according to their heights, the tallest being at the back and the shortest in the front. F is between B and A.E is shorter than D but taller than C who is taller than A. E and F have two boys between them. A is not shortest among them.
Where is E?

Choose the correct answer:

Explanation

1. Analyze the height constraints:

$E$ is shorter than $D \implies E < D$
$E$ is taller than $C \implies C < E$
$C$ is taller than $A \implies A < C$

Combining these: $A < C < E < D$ .

2. Place the group $F, B,$ and $A$ :

$F$ is between $B$ and $A$ . This means the sequence is either $(B, F, A)$ or $(A, F, B)$ .
We already know $A < C < E < D$ . If $A$ is part of the $B-F-A$ group, and $A$ is shorter than $C, E,$ and $D$ , then $A, F,$ and $B$ must be toward the front of the line.

3. Use the "two boys between E and F" clue:

We have the order: $A < C < E < D$ .
If we place $F$ and $E$ with two boys between them:
- If $F$ is at position $2$ , then $E$ must be at position $5$ (leaving $3$ and $4$ empty).
- If $F$ is at position $2$ , then $B$ and $A$ must be at $1$ and $3$ . Since "A is not shortest," $B$ must be at $1$ and $A$ must be at $3$ .
- Now we have: $B(1) < F(2) < A(3)$ .

4. Finalize the arrangement:

From step 1, we have $A < C < E < D$ .
Since $A$ is at $3$ :
- $C$ must be at $4$ .
- $E$ must be at $5$ .
- $D$ must be at $6$ .
Final Order (Shortest to Tallest): $B < F < A < C < E < D$ .

5. Determine E's position:

Looking at the final order $B - F - A - C - E - D$ , we can see that $E$ is positioned between D and C.

Conclusion:

$E$ is between $D$ and $C$ .

Correct Option:

(c) Between D and C