NIMCET 2012 — Reasoning PYQ

Q: How do I solve NIMCET 2012 Reasoning questions?

Practice NIMCET 2012 Reasoning previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Reasoning questions?

NIMCET Reasoning questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2012 — Reasoning PYQ

NIMCET | Reasoning | 2012

The missing number in the given series $3, 6, 6, 12, 9, \dots, 12$ is

Choose the correct answer:

Explanation

1. First Series (Odd Positions) The terms at the 1st, 3rd, 5th, and 7th positions are:

3, 6, 9, 12

Logic: Each term increases by adding 3 ( $+3$ ):

$3 + 3 = 6$
$6 + 3 = 9$
$9 + 3 = 12$

2. Second Series (Even Positions) The terms at the 2nd, 4th, and 6th positions (where our missing number is) are:

6, 12, \dots

Logic: Each term increases by adding 6 ( $+6$ ) or by multiplying by 2 ( $\times 2$ ):

$6 + 6 = 12$
$12 + 6 = 18$

Alternatively, if we check the gap:

Position 2: $6$
Position 4: $12$
Position 6: $18$

Conclusion: Following the logic of the second series ( $+6$ ), the missing number is 18.

Correct Option:(b) 18